Question: Let A and B be two events, such that P(A)>0 a.) show P(B|A)+P(B'|A)=1 b.) Prove that is P(B|A)>P, then P(B'|A) < P(B') (use part a

Let A and B be two events, such that P(A)>0
a.) show P(B|A)+P(B'|A)=1
b.) Prove that is P(B|A)>P, then P(B'|A) < P(B') (use part a to solve part b)

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a Using the definition of conditional probability we see that PBA PBA ... View full answer

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