Question: Let A be a ring. We say that a A-module M is surjectively-free over A if A = X fHomA(M,A)] f(M) Prove that if B

Let A be a ring. We say that a A-module M is surjectively-free over A if A = X fHomA(M,A)] f(M) Prove that if B is a surjectively free A-algebra, then 1) For any ideal I of A, IB A = I 2) The map Spec(B) Spec(A) is surjective

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