Question: Let A = begin{bmatrix} 0 & 1 0 & 0 end{bmatrix}. Find a basis of the kernel of the linear transformation L(mathbf{x}) = Amathbf{x}.
Let A = \begin{bmatrix} 0 & 1 \\ 0 & 0 \end{bmatrix}. Find a basis of the kernel of the linear transformation L(\mathbf{x}) = A\mathbf{x}. NOTE: Since there is no pivot in column 1, x_1 is a free variable. Let x_1 = s and find a basis for N(A)
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