Question: Let A[1..n] be an array of n elements. An element x is called a majority element in A[1..n] if Card({ i | A[i] = x

Let A[1..n] be an array of n elements. An element x is called a majority element in A[1..n] if Card({ i | A[i] = x }) > 2n/3.
Give an O(n) algorithm that decides whether A[1..n] contains a majority element, and if so finds it.

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