# Let ABC be any triangle with BCA not equal to 120. Let ACP,CBQ be equilateral triangles built

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## Question:

Let ABC be any triangle with ∠BCA not equal to 120◦. Let ACP,CBQ be equilateral triangles built on the sides AC,BC outside the triangle ABC. Prove that if the points A, B, Q, P lie on a common circle, then |AC| = |BC|.

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