Question: Let ALL_DFA A = {(A) | A is a DFA and L(A) = sigma* (where sigma is the alphabet of A). Show that ALL_DFA is

Let ALL_DFA A = {(A) | A is a DFA and

Let ALL_DFA A = {(A) | A is a DFA and L(A) = sigma* (where sigma is the alphabet of A). Show that ALL_DFA is decidable

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