Question: Let {an} (n>=1)be a sequence for which a(n+1) = (3an+1)/(an+3) for n>=1 (a) Prove that, if a 1 > -1, the sequence {a n }

Let {an} (n>=1)be a sequence for which a(n+1) = (3an+1)/(an+3) for n>=1

(a) Prove that, if a 1 > -1, the sequence {a n } converges.

Hint: consider the cases -1 < an <1, 1

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