Let $D$ be the region inside $r=2sin$ and outside $r=2cos$ in the first quadrant. Then ${}_D\frac{1}{x^2+y^2}dA=$

a$.{\displaystyle \underset{\frac{}{4}}{\overset{}{}}}{\displaystyle \underset{0}{\overset{2sin}{}}}\frac{1}{r}drd$

b$.{\displaystyle \underset{0}{\overset{}{}}}{\displaystyle \underset{2cos}{\overset{2sin}{}}}\frac{1}{r^2}drd$

c$.{\displaystyle \underset{0}{\overset{\frac{}{2}}{}}}{\displaystyle \underset{0}{\overset{2sin}{}}}\frac{1}{r}drd$

d$.{\displaystyle \underset{\frac{}{4}}{\overset{\frac{}{2}}{}}}{\displaystyle \underset{2cos}{\overset{2sin}{}}}\frac{1}{r}drd$

e$.{\displaystyle \underset{\frac{}{4}}{\overset{\frac{}{2}}{}}}{\displaystyle \underset{2sin}{\overset{2cos}{}}}\frac{1}{r^2}drd$