Question: let dfs [ 2 0 , 1 , 5 , 1 8 , 9 0 , 6 0 , 5 2 , 6 0 ,

let dfs [20,1,5,18,90,60,52,60,6,61,43,52);
let x = null
let a null:
for (let b=0; b dfs. length: b++){
if (x = null){
x = dfs [b];
continue;
if (a== null){
if (x > dfs [b]){
a=x;
x = dfs[b];
continue;
} else {
if (x == dfs[b]){
continue;
}
a = dfs[b];
continue;
}
if (x dfs [b]){
continue;
if (x dfs[b]){
x = dfs [b];
} else if (x = dfs (b) && xa)(
if (a dfs[b])(
continue;
2
a= dfsibl

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Programming Questions!