Question: let dfs [ 2 0 , 1 , 5 , 1 8 , 9 0 , 6 0 , 5 2 , 6 0 ,
let dfs ;
let x null
let a null:
for let b; b dfs length: b
if x null
x dfs b;
continue;
if a null
if x dfs b
ax;
x dfsb;
continue;
else
if x dfsb
continue;
a dfsb;
continue;
if x dfs b
continue;
if x dfsb
x dfs b;
else if x dfs b && xa
if a dfsb
continue;
a dfsibl
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