Question: Let f : ( 0 , 1 / 3 ] R such that f ( x ) = x ^ 2 . Show that f

Let f : (0,1/3] R such that f (x)= x^2. Show that f (x)< x.Show that f has no fixed point on (0,1/3]. Show that the function f(x)=1/1+x^2 from [0,) to [0,) has a fixed point c

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