Question: Let f be a differentiable function with f (2) =-4, f (2) = 1, f(8) = -6, and f'(8) = 3. Let the function g(x)

Let f be a differentiable function with f (2) =-4, f (2) = 1, f(8) = -6, and f'(8) = 3. Let the function g(x) = f (2x-). Write the equation of the line tangent to the graph of g at the point where x = 2

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