Question: Let f be a non-negative function defined on the interval [0, 1]. If [1-(f'(t)) dt =ff(t)dt, 0x 1, and 0 f(0) = 0, then
Let f be a non-negative function defined on the interval [0, 1]. If [1-(f'(t)) dt =ff(t)dt, 0x 1, and 0 f(0) = 0, then (A) f ( ) < = + and () >= f 2 3 () f ( ) < 1/1/ and f 1 () = =+ and f() >= 3 3 1 1 (+) >= and f()
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