Let $f$ be the function

$f(x)=\{\begin{array}{ccc}-3x^2& \text{f}\text{o}\text{r}& x2\\ -14-x& \text{f}\text{o}\text{r}& x>2\end{array}$

Compute the left$-$ and right$-$hand limits at $x=2$ and determine whether $f$ is left$-$continuous, right$-$continuous, or continuous at that point.

$($Use symbolic notation and fractions where needed.$)$

$\underset{x{2}^{-}}{lim}f(x)=$

$$

$\underset{x{2}^{+}}{lim}f(x)=$

$$