Question: Let f : R - Rm, q : Rm -> R and w a differential 1-form in Rm. Then dg is a differential 1-form in

Let f : R" - Rm, q : Rm -> R and w a differential 1-form in Rm. Then dg is a differential 1-form in Rm and g((f) ) : R" -> R. (a) Show that f*(dg) = d(g(f)). (b) Show that f*(dw) = d(f* (w)), where d is the exterior derivative of differential forms

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