Question: Let f ( t ) = 6 t 3 + 4 and g ( x ) = 1 x 6 t 3 + 4 d

Let f(t)=6t3+4 and g(x)=1x6t3+4dt.
Then by FTC1, we know that g'(x)=f(x)=
Let f ( t ) = 6 t 3 + 4 and g ( x ) = 1 x 6 t 3 +

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