Let $f(t)=F^{\text{'}}(t).$ Enter the integral ${\displaystyle \underset{a}{\overset{b}{}}}f(t)dt$ and evaluate it using the Fundamental Theorem of Calculus.

$F(t)=4t^{2}8t$;$a=2,b=8$

Enter the integral.

${\displaystyle \underset{a}{\overset{b}{}}}f(t)dt={\displaystyle \underset{a}{\overset{\phantom{}}{}}}()dt$

Evaluate the integral.

${\displaystyle \underset{0}{\overset{h}{}}}f(x)dx=$

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