Question: Let f ( x ) = 2 - 3 ( x 1 ) o ( x 1 ) , as x - 1 . It's

Let f(x)=2-3(x1)o(x1), as x-1. It's FALSE that
Select one:
f'(-1)=-3
it is not possible to determine the equation of the tangent line to the graph of f at (-1,f(-1))
f is differentiable at x=-1
f is continuous at x=-1
f(-1)=2
Let f ( x ) = 2 - 3 ( x 1 ) o ( x 1 ) , as x - 1

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