Let

$f(x)=\frac{3}{\sqrt[5]{2x^5+6x^2}}$

Using the Chain Rule and WITHOUT algebraic simplification, the derivative $off(x)is$ found $tobe$:

$f^{\text{'}}(x)=$

$-\frac{3}{5}(10x^4+12x{)}^{-\frac{6}{5}}$

$(10x^4+12x{)}^{-\frac{1}{5}}(10x^4+12x)$

$-\frac{3}{5}(2x^5+6x^2{)}^{-\frac{6}{5}}(10x^4+12x)$

$-\frac{3}{5}(2x^5+6x^2{)}^{-\frac{6}{5}}$

None $of$ the above.