Let $f(x)=\{\begin{array}{cc}{x}^{2}sin(\frac{1}{x}),& x<mn>0</mn>\\ \sqrt[\phantom{2}]{x},& x>0\end{array}$

Find $($a$)\underset{?}{lim}f(x)$ and $($b$)\underset{?}{lim}f(x),$ then use limit definitions to verify your findings.

$x{0}^{},x{0}^{-}$

$($c$)$ Based on your conclusions in parts $($a$)$ and $($b$),$ can you say anything about $\underset{x0}{lim}f(x)?$ Give reasons for your answer.

$($a$)\underset{x{0}^{}}{lim}f(x)=$