Question: Let f(a:) = 103: + 5 36:. Then the equation of the tangent line to the graph of f(a:) at the point (0,2) is given

Let f(a:) = 103: + 5 36:". Then the equation of

the tangent line to the graph of f(a:) at the point (0,2)

Let f(a:) = 103: + 5 36:". Then the equation of the tangent line to the graph of f(a:) at the point (0,2) is given by y = ma: + b for

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