Question: Let f(n)= 32n 4 + 12 n 2 log n . Then f(n)= O (?), f(n)= (?), f(n)= (?) Replace question marks with the correct

Let f(n)= 32n4+ 12 n2 log n . Then f(n)= O (?), f(n)= (?), f(n)= (?)

Replace question marks with the correct answer (we look for the tightest bound once possible). Choose the correct case from the following options:

a. f(n)= O(n4), f(n)= (n4), f(n)= (n4)

b. f(n)= O(n4), f(n)= (n2 log n 2), is not applicable

c. None of the cases are correct.

d. f(n)= O(log n), f(n)= (log n), f(n)= (log n)

e. f(n)= O(n2), f(n)= (n2), f(n)= (n2)

f. f(n)= O(n2 log n), f(n)= (n2 log n), f(n)= (n2 log n)

g. f(n)= O(n4), f(n)= (n2), is not applicable

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