Question: Let f(n)= 32n 4 + 12 n 2 log n . Then f(n)= O (?), f(n)= (?), f(n)= (?) Replace question marks with the correct
Let f(n)= 32n4+ 12 n2 log n . Then f(n)= O (?), f(n)= (?), f(n)= (?)
Replace question marks with the correct answer (we look for the tightest bound once possible). Choose the correct case from the following options:
a. f(n)= O(n4), f(n)= (n4), f(n)= (n4)
b. f(n)= O(n4), f(n)= (n2 log n 2), is not applicable
c. None of the cases are correct.
d. f(n)= O(log n), f(n)= (log n), f(n)= (log n)
e. f(n)= O(n2), f(n)= (n2), f(n)= (n2)
f. f(n)= O(n2 log n), f(n)= (n2 log n), f(n)= (n2 log n)
g. f(n)= O(n4), f(n)= (n2), is not applicable
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