Let F(r)=f(r).e, where r is a radial vector, r= [ r | is its magnitude, e,=r/r is the unit vector to the radial direction and f(r) = 6 3 . The volume V is a solid sphere with center at the origin and radius R = 1 . The surface, dV denotes the sphere's boundary. Using the Divergence theorem (Gauss' theorem) calculate the following surface integral (surface normal pointing outwards) : - F(r) . dS, av Enter the numeric value of the integral below giving your answer to two decimal places. Hint: You may wish to use the following formula for divergence of radial function: f ( r) f (r) f (r) V = ( V . r) +r. V