Question: Let f(x) be a function that has a Taylor Series centred at x = 6 given by 2nn f(x) = (3n + 1)! n=2
Let f(x) be a function that has a Taylor Series centred at x = 6 given by 2nn f(x) = (3n + 1)! n=2 converges. What is the smallest value of k for which the derivative f(^) (6) 0? k = . What is the value of this derivative? (k) (6) -(x 6) n +2
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