Let f(x) be continuous on [0,1] and differentiable on (0,1). Suppose f(0) = (1) = 0...

Transcribed Image Text:

Let f(x) be continuous on [0,1] and differentiable on (0,1). Suppose f(0) = (1) = 0 and f() = 1, show that there exists x0 = (0, 1) such that f'(x0) = 1. Let f(x) be continuous on [0,1] and differentiable on (0,1). Suppose f(0) = (1) = 0 and f() = 1, show that there exists x0 = (0, 1) such that f'(x0) = 1.