Question: Let f(x) = vx2 . We see that for any negative x, x = -|x], and, therefore, f(x) = f(-(x)) = (-x ) = |x/=

![x, x = -|x], and, therefore, f(x) = f(-(x)) = (-x )](https://s3.amazonaws.com/si.experts.images/answers/2024/06/666612e30b708_538666612e2db83c.jpg)
Let f(x) = vx2 . We see that for any negative x, x = -|x], and, therefore, f(x) = f(-(x)) = (-x ) = \\|x/= ? Hence vx2 # x. Rather we see that vx2 = (x|. The domain of f(x) = vx2 is (-co, co) and the range is [0, co). For your viewing pleasure we've included a graph of y = f(x): y
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