Question: Let f(x) = -x + 4. (a) Sketch the graphs of f(x), f(f(x)), f(f(f(x))) on the interval -2 x 10. y MO -2 10

Let f(x) = -x + 4. (a) Sketch the graphs of f(x),

Let f(x) = -x + 4. (a) Sketch the graphs of f(x), f(f(x)), f(f(f(x))) on the interval -2 x 10. y MO -2 10 X = -2 8 6 y 10 HAXH 8 2 f(x) f(x) RRRX)D 2 4 RRRX))) This answer has not been graded yet. 6 8 8 10 10 -2 (d) Give a quadratic function whose fixed points are x = -5 and x = 6. f(x) = y 10 -2 8 fifie of fix) 2 () y 10 2 Met ix) 2 4 tro 4 6 6 8 8 10 (b) Your graphs should all intersect at the point (8, 8). The value x = 8 is called a fixed point of the function f(x) since f(8) = 8; that is, 8 is fixed-it doesn't move when f is applied to it. Give an explanation for why 8 is a fixed point for any function f(f(f(...f(x)...))). 10 X (c) Linear functions (with the exception of f(x) = x) can have at most one fixed point. Quadratic functions can have at most two. Find the fixed points of the function g(x)=x-12. (Enter your answers as a comma-separated list.)

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