Let f(x) = x2 - 10x on [ - 2, 4] . Use the IVT to determine if there is a solution to f(x) = - 9 in the interval between -2 and 4. If so, find the value of c in the interval such that f(c) = - 9. f(x) is continuous on [ - 2, 4] O -9 is between f( - 2) = 24 and f(4) = - 24 C = 1 f(x) is continuous on [ - 2, 4] O -9 is not between -2 and 4 so the IVT does not apply f(x) is continuous on [ - 2, 4] O 9 is between f( - 2) = 24 and f(4) = - 24 C = 1, c=9 f(x) is continuous on [ - 2, 4] O 9 is between f( - 2) = 24 and f(4) = - 24 C=9