Let F(x, y, z) = 2xi + (y - 1) j + xzk be a vector field and S be the surface with equation y = e*+ 1 described in the following figure. Taking = (1, 74: 0) N = Then the unit normal vector that determines the orientation of S is y=e'+1 S F . N ds The double integral that allows to calculate the integral of is 6 2In(y - 1) - y +1 1+ (1 - y)-2 dy dz B (2In(y - 1) -y+1) dy dz ") 1 1 ," (2 1 ( y - 1 ) - y + 1 ) dy d . D) (y - 1 - 2In(y - 1)) dydz