Let f(x):=1/x^2, x not equal 0, x belongs R a) Determine the direct image f(E) where E:=
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Question:
Let f(x):=1/x^2, x not equal 0, x belongs R
a) Determine the direct image f(E) where E:= (x belongs R : 1<=x<=2)
b) Determine the inverse image f^(-1)(G) where G:= (x belongs R : 1<=x<=4)
My Solution:
A) Let f: R -> R be defined by f(x):=1/x^2. Then, the direct image of the set E:=(x:1<=x<=2) is the set f(E)=(y:1<=x<=1/4).
If G:= (y : 1<=x<=4), then the inverse image of G is the set f^-1 (G)=(x:
And here I don't quite understand how to find an inverse image. Please help.
Related Book For
Introduction to Real Analysis
ISBN: 978-0471433316
4th edition
Authors: Robert G. Bartle, Donald R. Sherbert
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