Question: Let f(x)=1x2on(0,1].(a) We've only defined U(f) for a bounded function on a closed, bounded set. Ifwe tryto ignore those requirements and compute U(f) anyway, what

Let f(x)=1x2on(0,1].(a) We've only defined U(f) for a bounded function on a closed, bounded set. Ifwe tryto ignore those requirements and compute U(f) anyway, what goes wrong?(b) Define f(0):=0,to extend the domain offto0,1. Again ignoring the fact that fis unbounded, what would U(f)be?(c) Compute 01f(x)dx, with careful justification, using the results of this section.

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