Let $gbe$ a continuous function, and suppose $we$ know the following:

${\displaystyle \underset{0}{\overset{3}{}}}g(x)dx=12$

${\displaystyle \underset{3}{\overset{6}{}}}g(x)dx=11$

Then,

${\displaystyle \underset{0}{\overset{6}{}}}g(x)dx=$

${\displaystyle \underset{0}{\overset{3}{}}}(g(x)+x)dx=$

${\displaystyle \underset{3}{\overset{6}{}}}(g(x)+9)dx=$