Question: Let H ( x ) = SHA - 2 5 6 ( x ) m o d 1 0 Is H ( x ) a

Let H(x)=SHA-256(x)mod10
Is H(x) a collision resistant hash function? If yes, describe why. If no, how would you find a collision?
Let x=x1||x2||dots||xn where each piece xi is 64 bits long.
Let G(x)=x1H(x1)||x2H(x2)||dots||xnH(xn), where xiH(xi) is regular exponentiation, and H is as defined above.
Is G(x) collision resistant? If yes, describe why. If no, find a collision.
(Hint: What if x is only a single piece?)
 Let H(x)=SHA-256(x)mod10 Is H(x) a collision resistant hash function? If yes,

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