Question: Let m: [0,1) -> [0,1) be the function defined by m(x) = 2x(mod 1). Show that the set of periodic points of m is dense

Let m: [0,1) -> [0,1) be the function defined by m(x) = 2x(mod 1). Show that the set of periodic points of m is dense in [0,1); i.e., for an arbitrary point x = x1x2x3..., exhibit the sequence of periodic points that approximate it. (No justification needed.)

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