Let p, q, r be nonzero real numbers that are, respectively, the 10th, 100th and 1000th terms of a harmonic progression. Consider the system of linear equation (I) (II) (III) (IV) If List-I 9 -=10, then the system of linear equations r x+y+z=1 10x + 100y + 1000z = 0 grx + pry + pqz = 0 has If P100, then the system of linear r equations has If P10, then the system of linear equation 9 has If P=10, then the system of linear equations 9 has The correct option is: (A) (I) (T); (II) (R); (III) (S); (IV) (T) (B) (I) (Q); (II) (S); (III) (S); (IV) (R) (C) (1) (Q); (II) (R); (III) (P); (IV) (R) (D) (I) (T); (II) (S); (III) (P); (IV) (T) (P) x = 0, y = (Q) 10 X=- 9 10 9 (S) no solution List-II 1 1 9 z = 0 as a solution (R) infinitely many solutions (T) at least one solution