Question: Let s(t) = t - 2t + 15 where s represents the position (displacement), at time t, of an object movin on a straight line,

 Let s(t) = t - 2t + 15 where s represents
the position (displacement), at time t, of an object movin on a

Let s(t) = t - 2t + 15 where s represents the position (displacement), at time t, of an object movin on a straight line, where t is measured in seconds. Consider such an object over the time interval [0, 10 Determine the position of the object at t = 0 and t = 10. The object's position at t = 0 is feet The object's position at t = 10 is feet Determine the average rate of change of the object over the time interval [0, 10]. The object's average rate of change over [0, 10] is: ft/sec Determine the instantaneous rate of change (velocity), speed, and acceleration of the object at t The object's velocity at t = 4 is ft/sec The object's speed at t = 4 is ft/sec The object's acceleration at t = 4 is ft/sec2 At what time over [0, 10], if any, did the object change directions? If multiple solutions exist, enter solutions using a comma-separated list. O The object changed directions at I = O The object did not change directions over [0, 10]

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