Question: Let T be the linear transformation T : R 5 R 5 below T ( x 1 , x 2 , x 3 , x

Let T be the linear transformation T:R5R5 below
T(x1,x2,x3,x4,x5)=(x1+x5,2x1+3x2-3x5,3x3+x4,3x4,x5)
The characteristic polynomial of T is
(t)=(t-1)2(t-3)3
In the parts below, you will compute an ordered Jordan basis F and Jordan blocks for MFF(T).(Click to open and close sections below).
Write x1asx1 and x2asx2 etc.
(A) Eigenvalue t=1
(B) Eigenvalue t=3
(T-3)(x1,x2,x3,x4,x5)=(-21+x5,21-354,0,-25)
dim(ker(T-3))=2
(T-3)2(x1,x2,x3,x4,x5)=(41-45,-41+85,0,0,45)
dim(ker(T-3)2)=3
(T-3)3(x2,x2,x3,x4,x5)=(-81+125,81-205,0,0,-85)
dim(ker(T-3)3)=3
Jordan Basis =(II)
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 Let T be the linear transformation T:R5R5 below T(x1,x2,x3,x4,x5)=(x1+x5,2x1+3x2-3x5,3x3+x4,3x4,x5) The characteristic

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