Let us consider the following:

$A=\frac{{20}^3{35}^4}{{14}^2{5}^8}etB=\frac{10}{3}-\frac{3}{4-\frac{7}{5}}$

$A=2^4{5}^2{7}^2$

$A=2^4{5}^{-1}{7}^2$

$A=257^2.$

$B=\frac{85}{39}.$

$B=-\frac{67}{15}.$

$B=17.$