Question: Let X 1 ,X 2 ,X 3 be a random sample from a uniform distribution [0, 10]. Show that the MSE of 4/3*X 3 is

Let X1,X2,X3 be a random sample from a uniform distribution [0, 10]. Show that the MSE of 4/3*X3 is 6.66666, and MSE of 3.6/3*X3 is 6.4.

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