Question: Let X and Y be two discrete random variables. Assume the table below represent the joint probability distribution between X and Y. Joint Probability Mass

Let X and Y be two discrete random variables. Assume the table below represent the joint probability distribution between X and Y.

Joint Probability Mass Function of X and YY=1Y=3Y=5Y=6X=10.020.010.010.06X=20.050.060.020.07X=30.070.030.090.51

Find the P(X2,Y5)P(X2,Y5). Answer for part 1 [The answer should be a number rounded to five decimal places, don't use symbols such as %]

Find the P(X2,Y>5)P(X2,Y>5). Answer for part 2 [The answer should be a number rounded to five decimal places, don't use symbols such as %]

Find the FX,Y(3,5)FX,Y(3,5). Answer for part 3 [The answer should be a number rounded to five decimal places, don't use symbols such as %]

Find the P(X=2/Y=3)P(X=2/Y=3). Answer for part 4 [The answer should be a number rounded to five decimal places, don't use symbols such as %]

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