Question: Let x be a random variable that represents the percentage of successful free throws a professional basketball player makes in a season. Let y be

 Let x be a random variable that represents the percentage ofsuccessful free throws a professional basketball player makes in a season. Lety be a random variable that represents the percentage of successful fieldgoals a professional basketball player makes in a season. A random sample

Let x be a random variable that represents the percentage of successful free throws a professional basketball player makes in a season. Let y be a random variable that represents the percentage of successful field goals a professional basketball player makes in a season. A random sample of * = 6 professional basketball players gave the following information. X 85 85 88 69 65 85 57 48 59 47 43 58 Given that S, * 4.144, a *5.796, b ~0.581, and x * 79.500, find a 90% confidence interval for (slope of the population regression line) and interpret its meaning. to = 2.132 O The 90% confidence interval for is from 0.180 to 0.983 and means that for every percentage increase in successful free throws, there is 90% confidence that the percentage of successful field goals increases by an amount between 0.18 and 0.98. O The 90% confidence interval for is from 0.200 to 0.962 and means that for every percentage increase in successful free throws, there is 90% confidence that the percentage of successful field goals increases by an amount between 0.20 and 0.96. O The 90% confidence interval for / is from 0.216 to 0.947 and means that for every percentage increase in successful free throws, there is 90% confidence that the percentage of successful field goals increases by an amount between 0.22 and 0.95. O The 90% confidence interval for is from 0.057 to 1.105 and means that for every percentage increase in successful free throws, there is 90% confidence that the percentage of successful field goals increases by an amount between 0.06 and 1.11. O The 90% confidence interval for is from 0.271 to 0.891 and means that for every percentage increase in successful free throws, there is 90% confidence that the percentage of successful field goals increases by an amount between 0.27 and 0.89.The following table shows the Myers-Briggs personality preferences for a random sample of 406 people in the listed professions. Occupation Extroverted Introverted |Row Total Clergy (all denominations) 63 44 107 M.D 69 95 164 Lawyer 55 80 135 Column total 187 219 406 Use the chi-square test to determine if the listed occupations and personality preferences are independent at c =0.05. Find the value of the chi-square statistic for the sample. O 9.66 O 0.01 O 12.01 O 0.17 O 7.89The following table shows the Myers-Briggs personality preferences for a random sample of 407 people in the listed professions. Occupation Extroverted Introverted |Row Total Clergy (all denominations) 64 42 106 M.D. 69 94 163 Lawyer 54 84 138 Column total 187 220 407 Use the chi-square test to determine if the listed occupations and personality preferences are independent at the 0.05 level of significance. What are the degrees of freedom? 0 4 0 3 O 2 0 5 0 6The following table shows the Myers-Briggs personality preferences for a random sample of 409 people in the listed professions. Occupation Extroverted Introverted Row Total Clergy (all denominations) 65 43 108 M.D. 68 94 162 Lawyer 57 82 139 Column total 190 219 409 Use the chi-square test to determine if the listed occupations and personality preferences are independent at =0.1. What is the level of significance? O 0.05 O 0.10 O 0.90 O 0.01 O 0.95

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