Question: Let X have a normal distribution with mean [1, = 40 and variance 02 = 25. Find P (36 g X g 52) 0 0.2480

 Let X have a normal distribution with mean [1, = 40and variance 02 = 25. Find P (36 g X g 52)0 0.2480 0 None of these 0 0.6844 0 0.7520 0 0.7799Let X have a normal distribution with mean ;1 = 1 and

Let X have a normal distribution with mean [1, = 40 and variance 02 = 25. Find P (36 g X g 52) 0 0.2480 0 None of these 0 0.6844 0 0.7520 0 0.7799 Let X have a normal distribution with mean ;1 = 1 and variance 0'2 = 1. What is the 11th percentile for the distribution of X? -1.23 -O.23 -1.29 -2.29 0.011 00000 According to Chebyshev's rule, the proportion of data within 2.5 standard deviations of the mean will be at least 0 84% o 60% 0 None of these 0 98.8% o 75% A probability density function is given by f(x) = x/18, for 0 Sx 56) 0, otherwise Which of the following statements are true? O None of these O P[1

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