Question: Let $X sim B(10,0.5)$ be a binomial random variable. What is $E(2X+3)$? The answer I got is 7, but I think it's wrong. Shouldn't it

Let $X \sim B(10,0.5)$ be a binomial random variable. What is $E(2X+3)$? The answer I got is 7, but I think it's wrong. Shouldn't it be 13? Since E(X) = np for binomial random variables, so E(X)=10*0.5=5. Using the linearity of expected values, I get E(2x+3)=2E(X)+E(3)=2*5+3=13.

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