Question: Let x (t) = +3 - 412 + t and y(t) = t2 - 6t + 3 At t = 3, (3) = y(3) =

Let x (t) = +3 - 412 + t and y(t)

= t2 - 6t + 3 At t = 3, (3) =

Let x (t) = +3 - 412 + t and y(t) = t2 - 6t + 3 At t = 3, (3) = y(3) = dt It= 3 = dy dt 1=3 = dy dx It=3 = tangent slope = speed (3) =

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