Let your Student ID be $20xy-$abcdef.

Let $p=10a-b$;$q=10c+d$;$r=10e-f$;$s=ab-cd+ef$

$(2023-103518)$ this is the student

Find the zero of the following equation:

number

$h(x)=-s-rx+q{x}^2-p{x}^3$

Use the approximate error as the exit criterion with a tolerance of $0\mathrm{.}01$

If $f$ is equal to $0,1$ and $2,$ use bisection method.

If $f$ is equal to $3,4$ and $5,$ use regula$-$falsi method.

If $f$ is equal to $6$ and $7,$ use fixed$-$point iteration method.

If $f$ is equal to $8$ and $9,$ use the newton raphson method.

Manually solve for the first $3$ iteration then you can use excel to show all the

iteration reaching $0\mathrm{.}01.($Non$-$anonymous question$(1)*\mathrm{.}4)(20$ Points$)$