Question: Lets attempt implementing an algorithm we have seen before: decimal to binary conversion (8 bits only) Create a function that takes in an unsigned int
- Lets attempt implementing an algorithm we have seen before: decimal to binary conversion (8 bits only)
- Create a function that takes in an unsigned int as its input and has a void output.
- The function will print the binary value of the unsigned int.
- Reference slides 39 and 40 from this week.
- ALGORITHM: Pick either this algorithm or the alternative one (you only have to implement one)
- Start with an exponent of 128.
- while(exponent >= 1)
- if (n >= exponent)
- print 1
- n = n exponent
- else if (n < exponent)
- print 0
- exponent = exponent / 2;
- if (n >= exponent)
- Alternative Algorithm - This one may be harder, but more interesting
- There is an alternative method you may consider (but may be more difficult).
- You may extract the actual bit from the unsigned int as shown on slide 47 from this week.
- Beware Endianness (ordering of bits).
- This means you may find the bits in the wrong order and need to reverse it.
- For example: 4 may print as 00100000
- Reverse your loop to have it print 00000100
- Create a main function that reads in an unsigned int value from the user.
- Pass the value to the function so its binary code is printed.
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