Question: Let's define someone at risk for sustaining a bone fracture as someone having a bone mineral density (BMD) below the 95 th percentile of the
Let's define someone at risk for sustaining a bone fracture as someone having a bone mineral density (BMD) below the 95th percentile of the age, race, and sex distribution scale. The average total body BMD for a white woman who is 55 years living in the US is 876139 mgcm-2. Mrs. Q has a BMD of 856 mgcm-2.
a. Calculate a Z-score for Mrs. Q's BMD
b. Is Mrs. Q at risk for a bone fracture?? Why or why not?
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