Question: Let's do a derivative in reverse! That is, instead of handing you a function f(x) and asking you to compute f 0 (x), let's start

Let's do a derivative "in reverse!" That is, instead of handing you a function f(x) and asking you to compute f 0 (x), let's start with the derivative and ask you to figure out which function was differentiated. To this end, suppose we have f 0 (x) = ? + 2x ? sin x + 2x ?3 . Which, if any, of the following functions could equal the original f(x)?

Let's do a derivative "in reverse!" That is, instead of handing you

Let's do a derivative "in reverse!" That is, instead of handing you a function f(x) and asking you to compute f'(x), let's start with the derivative and ask you to figure out which function was differentiated. To this end, suppose we have f'(x) = *+ 2x-sinc +2x 3. Which, if any, of the following functions could equal the original f(x)? (a) f(x) could equal 2 - cosr - 6r-4 (b) f(x) could equal ar + x3 + cosa - c-2+ 42 - v2022 (c) f(x) could equal ar + x3 + cosa + c-2 + v2 (d) f(x) could equal ar + r' + sinx - 62 + v17 + 2+ (e) None of the above

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