Let's integrate :1: I: f ab: . tr\" 3:2 25 We can use a substitution to express this integral in the form I : [9(a) do. The integral can then be evaluated as a function of u. Elut there are a few possibilities! Give your answers in terms of the variable a. . With the circle trig substitution :1: = 5 seem} the integrand becomes of\") = Q Q- Hence]r = @ l3 +0. . With the hvperbolic trig substitution 3 = 5 cosh[u) the integrand becomes at\") = Q Q- Hence]r = @ a +0. . With the substitution 1:2 = 3:2 52 the integrand becomes at\") = Q Q- Hence]r = @ a +0. . With the substitution at = 3:2 52 the integrand becomes at\") = Q Q- Hence]r = @ a +0. Any of these four answers can be reexpressed in terms of the original variable 11:, which leads to the conclusion: I = Q B +0