Question: Let's try another! 5x 8 3. Solve 2x 5x + 10 4- 2x 4 - (a) You know the drill! Factor the denominators! (NOTE: If

Let's try another! 5x 8 3. Solve 2x 5x + 10 4- 2x 4 - (a) You know the drill! Factor the denominators! (NOTE: If you need help factoring these polynomials, see Helping Handout: Lab IB) i. First denominator: Factor out a common monomial: 5x + 10 = 5 (x+2) ii. Second denominator: Factor out a common monomial: 4 - 2x = (2-x) iii. Third denominator: Factor (4-x2) = (2-x )(2+x ) (b) Rewrite with factored denominators: 5x 2x 8 NOTE: x + 2 is the same as 2 + x 5 (x + 2) 2(2 - x) (2 - x) (2+ x) (c) Find the restrictions: AND (d) Find the LCM: (e) Multiply every term by the LCM: 5x 2x 8 5 ( x + 2 ) 2(2 - x) (2- x) (2+3) (f) Cancel! Every term in the original denominators should cancel, or we made a mistake. Write the new equation: (g) Solve

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