lim z->0 of (cos(z))^(1/z^2) the answers say it is e^-1/2 but i cannot work out how to
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lim z->0 of (cos(z))^(1/z^2)
the answers say it is e^-1/2 but i cannot work out how to get there i am pretty sure you need to use l-hopitals rule
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